A and b can choose two from their own team and one from Whatsapp Mobile Number List the opposing team; c may choose three of the six candidates; summing the votes of the three judges, the top two with the most votes win; if the votes of the three judges are all abds, the abds will count 3 votes each, and Whatsapp Mobile Number List a second vote will be required. The following are known: a is inclined to abc, b is inclined to def, and c has an unknown attitude; a is a strong leader of team a with excellent performance; b is the backbone of team a for many years and is conscientious; c is the fresh blood of team a, growing rapidly.
Capable leader of team b with good Whatsapp Mobile Number List performance; e is a veteran of team b for many years, with stable output; f worked hard for team b, low-key and honest. Question: is there a strategy for a to make ab win with the Whatsapp Mobile Number List greatest probability? Choose two out of six, i don't even Whatsapp Mobile Number List want to forget about this. It's not necessarily more difficult to count, after all, only votes are counted, not points. That's also the permutation and combination of three 3 votes on six people.
The forward calculation is too troublesome, why not try the reverse? Whatsapp Mobile Number List better to count yourself more than the other party." in fact, if a, b and c are in the same team, and abcdef are six partners in the same team, and everyone trusts and benefits each other, there will be the following Whatsapp Mobile Number List implicit conditions: the decision of a, b and c is aimed at maximizing the interests of the team there is too little difference in the interests of choosing two of the six abcdef candidates at random in this case, there is no prisoner's dilemma game.